Q2
Let P = (x,y), M = (b, 2b), N = (x,0)
Slope of OM =2, So Slope of PM = -1/2
=> y-2b / x-b = -1/2
=> x+2y-5b =0 .........(1)
PM=root 5 x PN
So PM square = 5x PN square
=> (x-b)^2 + (y-2b)^2 = 5y^2 ...........(2)
Solving (1) and (2), get b=0 (rej) or y=b
Hence x=3b, and since y=b, get LOCUS of P is x=3y