[ n summation Xi summation (Xi)^2 [a [ sum Yi summation Xi summation (Xi)^2 summation (Xi)^3 b = sum XiYi summation (Xi)^2 summation (Xi)^3 summation (Xi)^4 ] c] sum (Xi^2 Yi)]
|| || || MATRIX A B Matrix C
我想問下點樣搵到個a,b,c ge 值出黎..(IN TERMS OF Xi 同Yi) 如果2邊都乘inverse of A (A-1)..好似好複雜咁..好難計呀.
有冇好友高手可以SHOW 個STEP 同ANSWER 出黎呀..THX!!
PonG
2010-01-21 23:49
SEM 課程真係深
雲佬~~SY
2010-01-22 00:00
引用第1樓pongpong123於2010-01-21 23:49發表的“”: SEM 課程真係深 [表情]