A.Maths高手請來 [復制鏈接]

Find the equation of the cirlce with the center on the x-axis and touching the line 2x-y-1=0 at (1, 1)


可唔可以教下我點做
感謝

center (x,0)
touching (1,1)

general form一代....入去

2條式2個unknown....


呢個方法唔得....

試緊...

噢...我再諗諗

x^2+y^2+Dx+Ey+F

用個center(1, 1)搵到D,E...

跟住個radius=個center同條line既distance...搵埋F..

連個radius點搵都唔知

引用第4樓ｊ摩連奴．狂妄於2007-05-15 00:42發表的“”:
x^2+y^2+Dx+Ey+F
用個center(1, 1)搵到D,E...
跟住個radius=個center同條line既distance...搵埋F..

center唔係(1, 1)丫

引用第5樓樂仔於2007-05-15 00:42發表的“”:
連個radius點搵都唔知 [表情]

書有講架..= =

radius=1/2(D+E-4F)^1/2

唔知有冇記錯

我連題目都未解得掂
Find the equation of the cirlce {with the center on the x-axis} {and touching the line 2x-y-1=0 at (1, 1)}

or

Find the equation of the cirlce with the center {on the x-axis and touching the line 2x-y-1=0 at (1, 1)}

引用第6樓樂仔於2007-05-15 00:43發表的“”:
center唔係(1, 1)丫 [表情]

咁...

center(h,0)同(1, 1)既distance=個center同條line既distance

搵到個h吧

引用第8樓樂仔於2007-05-15 00:46發表的“”:
我連題目都未解得掂
Find the equation of the cirlce {with the center on the x-axis} {and touching the line 2x-y-1=0 at (1, 1)}
or
.......

上面呀

引用第9樓ｊ摩連奴．狂妄於2007-05-15 00:47發表的“”:
咁...
center(h,0)同(1, 1)既distance=個center同條line既distance
.......

center同條line既distance應該搵唔到-0-
除非係in terms一d野...

引用第10樓ｊ摩連奴．狂妄於2007-05-15 00:48發表的“”:
上面呀 [表情]

icic...

引用第9樓ｊ摩連奴．狂妄於2007-05-15 00:47發表的“”:
咁...
center(h,0)同(1, 1)既distance=個center同條line既distance
.......

係唔係即係咁

(1-h)^2+(-1)^2= d

引用第11樓樂仔於2007-05-15 00:48發表的“”:
center同條line既distance應該搵唔到-0-
除非係in terms一d野...

ya