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這是一條 絕對會使你 迷失 的……"簡單"題目。 [復制鏈接]

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離線Bun
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只看該作者 30  發表于: 2007-07-18
A死既機會率(佢知道左b死硬)

=P(A死|B死)

=P(B死|A死)xP(A死)/P(B死)


唔係咁樣咩=v=?
咁計既話係1/2
離線Bun
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只看該作者 31  發表于: 2007-07-18
引用第30樓alvin_bun2007-07-18 18:44發表的“”:
A死既機會率(佢知道左b死硬)
=P(A死|B死)
=P(B死|A死)xP(A死)/P(B死)
.......

姐係j講果個:p哈
離線希汀加
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只看該作者 32  發表于: 2007-07-18
學過maths & stat 一定識,呢條題目係第一課教既
叫skyline出黎啦,佢數統拎A
離線jov
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只看該作者 33  發表于: 2007-07-18
引用第32樓希汀加2007-07-18 18:48發表的“”:
學過maths & stat 一定識,呢條題目係第一課教既 [表情]
叫skyline出黎啦,佢數統拎A

應數
離線希汀加
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只看該作者 34  發表于: 2007-07-18
引用第33樓j摩連奴.狂妄2007-07-18 18:51發表的“”:
應數 [表情]

J3學Applied maths架?
離線kylau
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只看該作者 35  發表于: 2007-07-18
This question is quite similar to a prob question I've seen in University

http://hkumath.hku.hk/~wkc/prob/prob.html

In a TV program, a player is asked to choose a key out of three indistinguishable keys A,B, and C. Only one of them is matched with the car, the prize of the winner Without the help of the TV program host, clearly the player only has a chance of 1/3 to get the car. The host is allowed to help the player in the following two ways: (A) The host can eliminate one wrong key from the three keys first before the player chooses one from the remaining two; or (B) the player can choose one key first without using it, then the host eliminates one wrong key from the remaining two keys. At this moment, the player is allowed to change his chosen key with the remaining one. Which option is more favorable? Why?

Very similar to (B) of this question.
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只看該作者 36  發表于: 2007-07-18
引用第34樓希汀加2007-07-18 18:54發表的“”:
J3學Applied maths架?

係呀...成功保到做AL
離線希汀加
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只看該作者 37  發表于: 2007-07-18
引用第36樓j摩連奴.狂妄2007-07-18 18:55發表的“”:
係呀...成功保到做AL [表情] [表情]

乜唔係一定係AS架咩?
離線jov
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只看該作者 38  發表于: 2007-07-18
引用第37樓希汀加2007-07-18 18:55發表的“”:
乜唔係一定係AS架咩?

有AL的....vector...mechanics
離線希汀加
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只看該作者 39  發表于: 2007-07-18
引用第38樓j摩連奴.狂妄2007-07-18 18:56發表的“”:
有AL的....vector...mechanics

vector amaths 學過啦
離線jov
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只看該作者 40  發表于: 2007-07-18
引用第39樓希汀加2007-07-18 18:57發表的“”:
vector amaths 學過啦 [表情]

amaths冇講過vector點用

其實都係同phy有關

vector moment..仲要係3d

用黎計force個d
離線icebati
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只看該作者 41  發表于: 2007-07-18
引用第35樓kylau2007-07-18 18:54發表的“”:
This question is quite similar to a prob question I've seen in University
http://hkumath.hku.hk/~wkc/prob/prob.html
In a TV program, a player is asked to choose a key out of three indistinguishable keys A,B, and C. Only one of them is matched with the car, the prize of the winner Without the help of the TV program host, clearly the player only has a chance of 1/3 to get the car. The host is allowed to help the player in the following two ways: (A) The host can eliminate one wrong key from the three keys first before the player chooses one from the remaining two; or (B) the player can choose one key first without using it, then the host eliminates one wrong key from the remaining two keys. At this moment, the player is allowed to change his chosen key with the remaining one. Which option is more favorable? Why?
.......

我都聽過, 一睇完就諗起呢條問題


不要忘記,足球是最快樂的!
離線希汀加
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只看該作者 42  發表于: 2007-07-18
引用第40樓j摩連奴.狂妄2007-07-18 18:59發表的“”:
amaths冇講過vector點用[表情] [表情]
其實都係同phy有關 [表情] [表情]
.......

我個fd al
pmaths A
applied maths(as) A
phy F左

我地成班恥笑左佢成個星期
離線麻凡
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只看該作者 43  發表于: 2007-07-18
引用第23樓lamho2007-07-18 18:04發表的“”:
係咪 關於 機會率既條件概率事呢?
樓主應該有答案呀?

有~

但係呢個題目都幾具爭議性, 所以應該先比各好友理性討論下再開估~
離線jov
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只看該作者 44  發表于: 2007-07-18
引用第42樓希汀加2007-07-18 19:00發表的“”:
我個fd al
pmaths A
applied maths(as) A
phy F左
.......

我:
pmaths AL
applied maths AL
phy AL

死得